125=y^-3/2

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Solution for 125=y^-3/2 equation: 


D( y )

y = 0

y = 0

y = 0

y in (-oo:0) U (0:+oo)

125 = (y^-3)/2 // - (y^-3)/2

125-((y^-3)/2) = 0

-1/2*y^-3 = -125 // : -1/2

y^-3 = 250

-3 < 0

1/(y^3) = 250 // * y^3

1 = 250*y^3 // : 250

1/250 = y^3

y^3 = 1/250 // ^ 1/3

y = (1/250)^(1/3)

y = (1/250)^(1/3)

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